Q. If a source is transmitting Electromagnetic Waves of frequency $8.196 \times 10^{6}$ Hz, then the wavelength of the Electromagnetic Waves transmitted from the source will be
A) 5090 cm
B) 4050 cm
C) 4230 cm
D) 3660 cm
Explanation
(d) Given , frequency of EM waves
$v = 8.196\ \times \ 10^{6}\ Hz$
Velocity of EM waves $(v)\ = \ 3\ \times \ 10^{8}\ m/s$
$\therefore$Wavelength of EM waves$\ \lambda = \frac{v}{V}$
$= \ \frac{3\ \times \ 10^{8}}{8.196\ \times \ 10^{6}}\ = \ 36.60\ m$
$= \ 3660\ cm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.