Q. The amplitude of the magnetic field part of a harmonic Electromagnetic Wave in vacuum is B$_{0}$=510 nT. What is the amplitude of the electric field part of the wave?
A) 140 NC$^{-1}$
B) 153 NC$^{-1}$
C) 163 NC$^{-1}$
D) 133 NC$^{-1}$
Explanation
(b) For an EM wave,$\ \frac{E_{0}}{B_{0}} = c\ or\ E_{0} = cB_{0}$
$\ = \ 3\ \times \ 10^{8}\ \times \ 510\ \times 10^{- 9}\ {NC}^{- 1}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \ 153\ {NC}^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.