Q. What is order of energy of X-rays (E$_{X}$), radio waves (E$_{R}$) and microwave (E$_{M}$)?
A) E$_{X}$ < E$_{R}$ < E$_{M}$
B) E$_{X}$ < E$_{M}$ > E$_{R}$
C) E$_{M}$ > E$_{X}$ > E$_{R}$
D) E$_{M}$ < E$_{R}$ < E$_{X}$
Explanation
(b) The wavelength of X-rays is of the order of $1\ \mathring{\mathrm{A}}\ to\ 100\ \mathring{\mathrm{A}}.$ The wavelength of radiowaves is of the order of $10^{9}\mathring{\mathrm{A}}\ to\ 10^{1.4}\mathring{\mathrm{A}}.\ \ $The wavelength of microwaves is of the order of $10^{7}\mathring{\mathrm{A}}\ to\ 10^{9}\mathring{\mathrm{A}}.$
Thus, $\lambda_{X} < \lambda_{M} < \lambda_{R}$
The waves with less wave length will have more energy.
Hence,
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E_{X}{> E}_{M} > E_{R}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.