Q. Dimensions of $\frac{1}{\mu_{0}\varepsilon_{0}}$, where symbols have their usual meanings, are
A) $\lbrack L^{- 1}T\rbrack$
B) $\lbrack L^{- 2}T^{2}\rbrack$
C) $\lbrack L^{2}T^{- 2}\rbrack$
D) $\lbrack LT^{- 1}\rbrack$
Explanation
(c) $c = \frac{1}{\sqrt{\mu_{0}\varepsilon_{0}}}\ \ \ or\ \ \frac{1}{\mu_{0}\varepsilon_{0}} = c^{2}$
$= \left\lbrack M^{0}{LT}^{- 1} \right\rbrack^{2} = \lbrack M^{0}L^{2}T^{- 2}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.