A circular ring of radius $r$ is placed in a homogenous magnetic field perpendicular to the plane of the ring. The field $B$ chnages with time according to the equation $B = kt$, where $k$ is a constant and $t$ is the time. The electric field in the ring is

Question

Dr. Abubacker · Accepted Answer

(c) $\oint\overrightarrow{\mathbf{E}}\mathbf{\bullet}\overrightarrow{\mathbf{dl}}\mathbf{=} - \frac{d\phi B}{dt}$
or $E 	imes 2\pi r = \frac{d}{dt}\left( Kt 	imes \pi r^{2} ight) = K\pi r^{2}$
or $E = \frac{Kr}{2}$

Q. A circular ring of radius $r$ is placed in a homogenous magnetic field perpendicular to the plane of the ring. The field $B$ chnages with time according to the equation $B = kt$, where $k$ is a constant and $t$ is the time. The electric field in the ring is

Explanation

Reviewed by Dr. Abubacker

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