Q. Instantaneous displacement current of 1.0 A in the space between the parallel plate of $1\ \mu F$ capacitor can be estabilished by changing potential difference of
A) $10^{- 6}Vs^{- 1}$
B) $10^{6}Vs^{- 1}$
C) $1\ Vs^{- 1}$
D) $0.1\ Vs^{- 1}$
Explanation
(b) $\frac{Q}{t} = \frac{CV}{t}\ or\ \ i_{D} = C\left( \frac{V}{T} \right)$
or $\frac{V}{t} = \frac{i_{D}}{C} = \frac{1.0}{10^{- 6}}\ Vs^{- 1} = 10^{6}\ Vs^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.