Q. Given figures show the arrangements of two lenses, The radii of curvature of all the curved surfaces are same. The ratio of the equivalent focal length of combinations $P,\ Q\ and\ R$ is

A) $1\ :1\ :1$
B) $1\ :1\ : - 1$
C) $2\ :1\ :1$
D) $2\ :1\ :2$
Explanation

(a) In given images, $P,\ Q$ and $R$ lenses in contact for $P$ combination of lenses
$\frac{1}{F_{P}} = \frac{1}{f} + \frac{1}{f} = \frac{2}{f}$
$F_{P} = \frac{f}{2}$
Similarly for $Q$ and $R$ combination
$F_{Q} = \frac{f}{2}$
$F_{R} = \frac{f}{2}$
Then $P\ :Q\ :R = 1\ :1\ :1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.