(b) When light passes from one medium to another, its frequency remains unchanged but it velocity (and hence, wavelength) changes.
$\ _{a}\mu_{g} = \frac{wavelength\ in\ air\ \left( \lambda_{a} \right)}{wavelength\ in\ glass\ \left( \lambda_{g} \right)}$
$\Rightarrow 1.6\ = \ \frac{5890}{\lambda_{g}}$
$\Rightarrow \lambda_{g} = \frac{5890}{1.6} = 3681\ \mathring{\mathrm{A}}\ $