(d) Critical angle for the material of prism $C = \sin^{- 1}\left( \frac{1}{\mu} \right) = \sin^{- 1}{\left( \frac{1}{1.5} \right) = 42{^\circ}}$ since angle of incidence at surface $AB(60{^\circ})$ is greater than the critical angle $(42{^\circ})$, so total internal reflection takes place