Q. A bucket contains some transparent liquid and its depth is 40 cm. On looking from above, the bottom appears to be raised up by 8 cm. The refractive index of the liquid is
A) 5/4
B) 5
C) 4/5
D) 8/5
Explanation
(a) Apparent shift $= t\left( 1 - \frac{1}{\mu} \right)$
$8 = 40\left( 1 - \frac{1}{\mu} \right)\ or\ \ \frac{1}{5} = 1 - \frac{1}{\mu}$
Or $\frac{1}{\mu} = \frac{4}{5}\ $or$\ \ \mu = \frac{5}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.