A convex lens is placed between object and a screen. The size of object is 3 cm and an image of height 9 cm is obtained on the screen. When the lens is displaced to a new position, what will be the size of image on the screen?

Question

Dr. Abubacker · Accepted Answer

(d) Form displacement method size of object, $O = \ \sqrt{I_{1}I_{2}}$
Here, $O$ = 3 cm, $I_{1}$ = 9 cm
$	herefore$ 3 = $\sqrt{9I_{2}}$
Or $I_{2}$ = 1 cm

Q. A convex lens is placed between object and a screen. The size of object is 3 cm and an image of height 9 cm is obtained on the screen. When the lens is displaced to a new position, what will be the size of image on the screen?

Explanation

Reviewed by Dr. Abubacker

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