Q. A ray of light is incident on the surface of separation of a medium at an angle $45{^\circ}$ and is refracted in the medium at an angle $30{^\circ}$. What will be the velocity of light in the medium
A) $1.96 \times 10^{8}\ m/s$
B) $2.12 \times 10^{8}\ m/s$
C) $3.18 \times 10^{8}\ m/s$
D) $3.33 \times 18^{8}\ m/s$
Explanation
(b) $\mu = \frac{c}{v} = \frac{\sin i}{\sin r} = \frac{\sin{45{^\circ}}}{\sin{30{^\circ}}}$
$\Rightarrow v = \frac{3 \times 10^{8}}{\sqrt{2}} = 2.12 \times 10^{8}\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.