Q. The critical angle of a medium with respect to air is $45{^\circ}.$ The refractive index of that medium will be
A) 1.72
B) 1.414
C) 2.12
D) 1.5
Explanation
(b) $\ \ _{1}\mu_{2} = \frac{1}{\sin c}\ = \frac{1}{\sin{45{^\circ}}}$
$\ \ \ \ \ \ \ \ \ = \frac{1}{1/\sqrt{2}} = \sqrt{2} = 1.414$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.