Q. The maximum magnification that can be obtained with a convex lens of focal length $2.5\ cm$ is (the least distance of distinct vision is $25\ cm$)
A) 10
B) $0.1$
C) $62.5$
D) 11
Explanation
(d) $m_{\max} = 1 + \frac{D}{f} = 1 + \frac{25}{2.5} = 11$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.