(c) Let the angle between the two mirrors be$\theta$, Ray $PQ$ is parallel to mirror $M_{1}$ and $RS$ is parallel to $M_{2}.$
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So, $\angle M_{1}\ RS\ = \angle ORQ = \angle\ M_{1}\ OM_{2} = \ \theta$
Similarly, $\angle M_{2}QP = \angle OQR = \ \angle M_{2}OM_{1} = \theta$
$\therefore$ In $\mathrm{\Delta}\ ORQ,\ 3\theta = 180{^\circ}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \theta = 60{^\circ}$