Q. An object is placed $12\ cm$ to the left of a converging lens of focal length $8\ cm$. Another converging of $6\ cm$ focal length is placed at a distance of $30\ cm$ to the right of the first lens. The second lens will produce

A) No image
B) A virtual enlarged image
C) A real enlarged image
D) A real smaller image
Explanation

(c) For lens (1) $\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{( - 8)} = \frac{1}{v} - \frac{1}{( - 12)}$
$\Rightarrow v = 24\ cm\ i.e.$ image $A'B'$ is obtained $6\ cm$ before the lens 2 or at the focus of lens 2. Hence final image formed by lens 2 will be real enlarged and it is obtained at $\infty$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.