(c) For lens (1) $\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{( - 8)} = \frac{1}{v} - \frac{1}{( - 12)}$
$\Rightarrow v = 24\ cm\ i.e.$ image $A'B'$ is obtained $6\ cm$ before the lens 2 or at the focus of lens 2. Hence final image formed by lens 2 will be real enlarged and it is obtained at $\infty$