The graph between sine of angle of refraction $(\sin r)$ in medium 2 and sine of angle of incidence $(\sin i)$ in medium 1 indicates that $( an{36{^\circ}} \approx \frac{3}{4})$

Question

The graph between sine of angle of refraction $(\sin r)$ in medium 2 and sine of angle of incidence $(\sin i)$ in medium 1 indicates that $(	an{36{^\circ}} \approx \frac{3}{4})$

Dr. Abubacker · Accepted Answer

(b) From graph, slope $= 	an\left( \frac{2\pi}{10} ight) = \frac{\sin r}{\sin i}$
Also $u_{1}\mu_{2} = \frac{\mu_{2}}{\mu_{1}} = \frac{\sin i}{\sin r} = \frac{1}{	an\left( \frac{2\pi}{10} ight)} = \frac{4}{3} \Rightarrow \mu_{2} > \mu_{1}$
It means that medium 2 is denser medium. So total internal reflection cannot occur

Q. The graph between sine of angle of refraction $(\sin r)$ in medium 2 and sine of angle of incidence $(\sin i)$ in medium 1 indicates that $(\tan{36{^\circ}} \approx \frac{3}{4})$

Explanation

Reviewed by Dr. Abubacker

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