Glass has refractive index $\mu$ with respect to air and the critical angle for a ray of light going from glass to air is $ heta$. If a ray of light is incident from air on the glass with angle of incidence $ heta$, the corresponding angle of refraction is

Question

Glass has refractive index $\mu$ with respect to air and the critical angle for a ray of light going from glass to air is $	heta$. If a ray of light is incident from air on the glass with angle of incidence $	heta$, the corresponding angle of refraction is

Dr. Abubacker · Accepted Answer

(c) $\ _{a}\mu_{g} = \frac{1}{\sin	heta} \Rightarrow \mu = \frac{1}{\sin	heta}\ \ \ldots(i)$
Now from Snell’s law $\mu = \frac{\sin i}{\sin r} = \frac{\sin	heta}{\sin r}$
$\Rightarrow \sin r = \frac{\sin	heta}{\mu}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ldots(ii)$
From equation (i) and (ii)
$\sin r = \frac{1}{\mu^{2}} \Rightarrow r = \sin^{- 1}\left( \frac{1}{\mu^{2}} ight)$

Q. Glass has refractive index $\mu$ with respect to air and the critical angle for a ray of light going from glass to air is $\theta$. If a ray of light is incident from air on the glass with angle of incidence $\theta$, the corresponding angle of refraction is

Explanation

Reviewed by Dr. Abubacker

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