Q. A double convex lens made out of glass (refractive index $\mu = 1.5)$ has both radii of curvature of magnitudes 20 cm. Incident light rays parallel to the axis of this lens will converge at a distance $d$ such that

A) $d = 10\ $cm
B) $d = \frac{20}{3}cm$
C) $d = 40\ cm$
D) $d = 20\ cm$
Explanation

(d) Use $d = f;$ where, $\frac{1}{f} = (\mu - 1)\frac{2}{R} = (1.5 - 1) \times \frac{2}{20} = \frac{1}{20}$
$\Rightarrow f = 20\ cm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.