Q. A fish at a depth of 12 cm in water is viewed by an observer on the bank of a lake. To what height the image of the fish is raised? (Refractive index of like water=4/3)

A) 9 cm
B) 12 cm
C) 3.8 cm
D) 3 cm
Explanation

(d) Apparent raise $= \ d\left( 1 - \frac{1}{\ _{a}\mu_{w}} \right)$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 12 \times \left( 1 - \frac{3}{4} \right) = 12 \times \frac{1}{4} = 3\ cm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.