(c) $\delta_{\Pr{ism}} = (\mu - 1)A = (1.5 - 1)4{^\circ} = 2{^\circ}$ $\therefore\ \delta_{Total} = \delta_{\Pr{ism}} + \delta_{Mirror}$ $= (\mu - 1)A + (180 - 20) = 2{^\circ} + (180 - 2 \times 2) = 178{^\circ}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.