(d) The image of object at infinity should be formed at $100\ cm$ from the eye
$\frac{1}{f} = \frac{1}{\infty} - \frac{1}{100} = - \frac{1}{100}$
So the power $= \frac{- 100}{100} = - 1\ D$
[Distance is given in $cm$ but $P = \frac{1}{f}$ in $metres$]