(b) Wavelength of a certain colour in air $\lambda_{air} = 600\ nm.$
Wavelength of a certain colour in glass of refractive index $\mu = 1.5$
$\therefore\lambda_{glass} = \frac{\lambda_{air}}{\mu_{glass}} = \frac{600}{1.5}$
$\lambda_{glass} = 400\ nm$
$Also,\ v_{glass} = \frac{v_{air}}{\mu_{glass}} = \frac{3 \times 10^{8}}{1.5}$
$v_{glass} = \ 2.0\ \times \ 10^{8}\ {ms}^{- 1}$