(a) According to Snell’s law
Refractive index, $\mu = \frac{\sin i}{\sin r}$
Given $i = 2r$
$\therefore\ \mu = \frac{\sin{2r}}{\sin{\ r}}$
Or $\mu = \frac{2\sin{r\cos r}}{\sin r}$
Or $\cos^{- 1}\frac{\mu}{2} = r$
$\Rightarrow i = 2\cos^{- 1}\left\lbrack \frac{\mu}{2} \right\rbrack$