Q. In a pond of water, a flame is held 2 m above the surface of water. A fish is at depth of 4 m from water surface. Refractive index of water is$\frac{4}{3}$. The apparent height of the flame from the eyes of fish is
A) 5.5 m
B) 6 m
C) $\frac{8}{3}\ m$
D) $\frac{20}{3}\ m$
Explanation
(d) Apparent height of flame above water surface.
$h' = \ \mu h = \frac{4}{3} \times 2 = \frac{8}{3}m$
Therefore, apparent height of the flame from the eye of fish
$= d + h' = 4 + \frac{8}{3} = \frac{20}{3}m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.