(b) $P_{1} + P_{2} = 9$ $P = \ P_{1} + P_{2} - dP_{1}P_{2}$ $\frac{27}{9} = 9 - \frac{20}{100} \times P_{1}P_{2}\ $ The above equation is correct for $P_{1} = 3\ and\ P_{2} = 6$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.