(a) $D_{F} = \frac{d^{2}}{\lambda}$ $D_{F} = \frac{3 \times 10^{- 3}(3 \times 10^{- 3})}{500 \times 10^{- 9}} = \frac{90}{5}m = 18m$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.