(d) $\frac{I_{center}}{I_{edge}} = \frac{\left( r^{2} + h^{2} \right)^{3/2}}{h^{3}}$
$\Rightarrow 8 = \frac{\left( r^{2} + h^{2} \right)^{3/2}}{h^{3}} \Rightarrow 2h = \left( r^{2} + h^{2} \right)^{1/2}$
$\Rightarrow 4h^{2} = r^{2} + h^{2} \Rightarrow 3h^{2} = r^{2} \Rightarrow h = \frac{r}{\sqrt{3}}$