Q. Critical angle for light going from medium (i) to (ii) is $\theta$. The speed of light in medium (i) is $v$ then speed in medium (ii) is
A) $v\left( 1 - \cos\theta \right)$
B) $v/\sin\theta$
C) $v/\cos\theta$
D) $v(1 - \sin\theta)$
Explanation
(b) $\ _{2}\mu_{1} = \frac{1}{\sin\theta} \Rightarrow \frac{\mu_{1}}{\mu_{2}} = \frac{1}{\sin\theta} \Rightarrow \frac{v_{2}}{v_{1}} = \frac{1}{\sin\theta} \Rightarrow \frac{v_{2}}{v} = \frac{1}{\sin\theta}$
$\Rightarrow v_{2} = \frac{v}{\sin\theta}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.