(d) $L = v_{0} + f_{e} \Rightarrow v_{0} = L - f_{e}$
Or ${\ v}_{0} = 19.2\ cm$
$\frac{1}{19.2} - \frac{1}{u_{0}} = \frac{1}{1.6}$
Or $- \frac{1}{u_{o}} = \frac{10}{16} - \frac{10}{192}$
Or $- \frac{1}{u_{o}} = \frac{120 - 10}{192} = \frac{100}{192}$
Or ${\ u}_{o} = - \frac{192}{110}\ $cm$\ = - 1.75\ $cm