(a) We know, $\frac{y}{D} \geq 1.22\frac{\lambda}{d}$ $\Longrightarrow D \leq \frac{yd}{1.22\lambda}$ $= \frac{10^{- 3} \times 3 \times 10^{- 3}}{1.22 \times 5 \times 10^{- 7}}$ $= \frac{30}{6.1} = 5\ m$ $\therefore\ \ D_{\max\ } = 5m$
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