Q. The critical angle for a medium is $60{^\circ}$. The refractive index of the medium is
A) $\frac{2}{\sqrt{3}}$
B) $\frac{\sqrt{2}}{3}$
C) $\sqrt{3}$
D) $\frac{\sqrt{3}}{2}$
Explanation
(a) $\mu = \frac{1}{\sin C} = \frac{1}{\sin{60{^\circ}}} = \frac{2}{\sqrt{3}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.