Q. Two lamps of luminous intensity of $8\ Cd$ and 32 $Cd$ respectively are lying at a distance of 1.2 $m$ from each other. Where should a screen be placed between two lamps such that its two faces are equally illuminated due to two sources

A) 10 $cm$ from 8 $Cd$ lamp
B) 10 $cm$ from 32 $Cd$ lamp
C) 40 $cm$ from 8 $Cd$ lamp
D) 40 $cm$ from 32 $Cd$ lamp
Explanation

(c) $I = \frac{L}{r^{2}} \Rightarrow \frac{L_{1}}{r_{1}^{2}} = \frac{L_{2}}{r_{2}^{2}}$
or $\frac{8}{x^{2}} = \frac{32}{(120 - x)^{2}}$
Solving it we get $x = 40\ cm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.