Q. An object is placed at a distance of 10 cm from a concave mirror of radius of curvature 0.6 m. Which of the following statements is incorrect?
A) The image is formed at a distance for 15 cm from the mirror
B) The image formed is real
C) The image is 0.5 times the size of the object
D) The image is 1.5 times the size of the object
Explanation
(a) $f = - \frac{0.6}{2} = - 0.3\ m = - 30\ cm$
$\frac{1}{v} + \frac{1}{- 10} = \frac{1}{- 30}$
$\frac{1}{v} = \frac{1}{10} - \frac{1}{30} = \frac{3 - 1}{30}$
Or $v = \frac{30}{2}cm = 15\ cm$
$m = - \frac{v}{u} = - \frac{15}{- 10} = 1.5$
Object lies between principal focus and pole. So, the image is virtual and erect
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.