(c) Number of images $= \frac{360{^\circ}}{\theta} - 1$
Where $\theta$ is in degrees, $\therefore 5 = \frac{360{^\circ}}{\theta} - 1$
or $\theta = \frac{360{^\circ}}{\theta} = 60{^\circ}$
New angle, $\theta^{'} = \theta - 30{^\circ} = 60{^\circ} - 30{^\circ} = 30{^\circ}$
Number of images $= \frac{360{^\circ}}{30{^\circ}} - 1 = 11$