Q. A ray of light falls on a transparent glass slab of refractive index 1.62.If the reflected ray and the refracted ray are mutually perpendicular, the angle of incidence is
A) $\tan^{- 1}{(1.62)}$
B) $\tan^{- 1}\left( \frac{1}{1.62} \right)$
C) $\tan^{- 1}{(1.33)}$
D) $\tan^{- 1}\begin{array}{r}
\left( \frac{1}{1.33} \right)
\end{array}$
Explanation
(a) Brewster discovered that when a beam of unpolarised light is reflected from a transparent medium (refractive index =$\mu$), the reflected light is completely plane polarized at a certain angle of incidence (called the angle of polarization $\theta_{p}$)
Also, $\mu = \tan\theta_{p}$
$\therefore$ Here, $\theta_{p} = \ \theta_{1} = \tan^{- 1}(1.62)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.