(d) If $\eta$ is the luminous efficiency of the bulb then luminous flux by $120\ watt$ at $555\ nm = \eta \times 120$
Let bulb of $P$ watt at $600\ nm$ produces the same luminous flux as by $120\ watt$ at $555\ nm$ then
$\eta \times 120 = \eta P \times 0.6 \Rightarrow P = \frac{120}{0.6} = 200\ watt$