Q. The index of refraction of diamond is 2.0, velocity of light in diamond in cm/s is approximately
A) $6\ \times \ 10^{10}$
B) $3.0\ \times \ 10^{10}$
C) $2\ \times 10^{10}$
D) $1.5\ \times \ 10^{10}$
Explanation
(d) Refractive index, $\mu_{d} = \frac{c}{v_{d}}$
Hence, $v_{d} = \frac{c}{\mu_{d}} = \ \frac{3 \times 10^{8}}{2}$
$= 1.5\ \times 10^{8}{ms}^{- 1} = 1.5 \times 10^{10}{cms}^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.