A 4 cm thick layer of water covers a 6 cm thick glass slab. A coin is placed at the bottom of the slab and is being observed from the air side along the normal to the surface. Find the apparent position of the coin from [image:9_image31.jpeg]

Question

Dr. Abubacker · Accepted Answer

(a) Using equation, the total apparent shift is
[image:9_image93.emf]
$s = h_{1}\left( 1 - \frac{1}{\mu_{1}} \right) + h_{2}\left( 1 - \frac{1}{\mu_{2}} \right)$
Or $s = 4\left( 1 - \frac{1}{4/3} \right) + 6\left( 1 - \frac{1}{3/2} \right)$
$= 3.0$ cm
Thus, $h = h_{1} + h_{2} - s = 4 + 6 - 3$
$= 7.0\ $cm

Q. A 4 cm thick layer of water covers a 6 cm thick glass slab. A coin is placed at the bottom of the slab and is being observed from the air side along the normal to the surface. Find the apparent position of the coin from

Explanation

Reviewed by Dr. Abubacker

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