Q. A convex mirror and a concave mirror has radii of curvature 10 cm each are placed 15 cm apart facing each other. An object is placed midway between them. If the reflection first takes place in the concave mirror and then in convex mirror, the position of the final image is
A) on the pole of the convex mirror
B) on the pole of the concave mirror
C) at a distance of 10 cm from convex mirror
D) at a distance of 5 cm from concave mirror
Explanation
(a) For concave mirror
$u = - \frac{15}{2}cm,v = ?$
$f = - \frac{10}{2}cm = - 5\ cm$
$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{- 5} - \frac{1}{- 15/2}$
$= - \frac{1}{5} + \frac{2}{15} = \frac{- 1}{15}$
Or $v = - 15\ cm$
Clearly, the position of the final image is on the pole of the convex mirror
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.