(c) $P = \frac{1}{f} = (\mu - 1)\left\lbrack \frac{1}{R_{1}} - \frac{1}{R_{2}} \right\rbrack$
$Hence,\ \ \ \frac{P_{2}}{P_{1}} = \left( \frac{\mu_{2} - 1}{\mu_{1} - 1} \right)$
$ie,\ \ \frac{P_{2}}{1} = \frac{1.6 - 1}{1.5 - 1}$
$Hence,\ P_{2} = 1.2$