Q. A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1 m from it. The image is formed at a distance of
A) 8/13 m in front of the mirror
B) 8/13 m behind the mirror
C) 4/9 m in front of the mirror
D) 4/9 m behind the mirror
Explanation
(d) $f = \frac{1.6}{2}m = 0.8m,u = - 1\ m$
$\frac{1}{v} = \frac{1}{0.8} - \frac{1}{- 1} = \frac{10}{8} + 1 = \frac{18}{8} = \frac{9}{4}$
Or $\ v = \frac{4}{9}m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.