Q. A large glass slab $\left( \mu = \frac{5}{3} \right)$ of thickness 8 cm is placed over a point source of light on a plane surface. It is seen that light emerges out of the top surface of the slab from a circular area of radius $R$ cm. What is the value of $R?$

A) 6 cm
B) 7 cm
C) 8 cm
D) 9 cm
Explanation

(a) $\frac{R}{t}\tan\theta_{C}$
[image:9_image102.emf]
Or $R = t\left( \tan\theta_{C} \right)$
But, $\sin\theta_{C} = \frac{1}{\mu} = \frac{3}{5}$
$\therefore\tan\theta_{C} = \frac{3}{4}$
$R = \frac{3}{4}t = \frac{3}{4}(8\ cm) = 6\ cm$
Hence, the answer is 6.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.