(b) For achromatic combination $\frac{f_{1}}{f_{2}} = - \frac{\omega_{2}}{\omega_{1}} = - \frac{0.036}{0.024} = - \frac{3}{2}\ $and $\frac{1}{f_{1}} - \frac{1}{f_{2}} = \frac{1}{90}$ Solving above equations we get $f_{1} = 30cm,\ f_{2} = - 45cm$
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