For compound microscope $f_{0} = 1\ cm,\ f_{e} = \ 2.5\ cm.$ An object is placed at distance 1.2 cm from object lens. What should be length of microscope for normal adjustment?

Question

Dr. Abubacker · Accepted Answer

(b) When final image formed at normal adjustment, then length of compound microscope,
$L = v_{0} + u_{e}\  = \frac{u_{0}f_{0}}{(u_{0} + f_{0})} + \frac{f_{e}D}{f_{e} + D}$
$= - \ \frac{- 1.2 	imes 1}{- 1.2 + 1} + \frac{2.5 	imes 25}{2.5 + 25}$
$6\  + \ 2.27\  = \ 8.27\  \approx \ 8.3\ cm$

Q. For compound microscope $f_{0} = 1\ cm,\ f_{e} = \ 2.5\ cm.$ An object is placed at distance 1.2 cm from object lens. What should be length of microscope for normal adjustment?

Explanation

Reviewed by Dr. Abubacker

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