(c) The refractive index of glass with respect to water is
$\ _{w}\mu_{g} = \frac{\ _{a}\mu_{g}}{\ _{a}\mu_{w}}$
Given,$\ _{a}\mu_{g} = 1.5,\ \ _{a}\mu_{w} = 1.33$
$\ _{w}\mu_{g} = \ \frac{1.5}{1.33} = 1.80$
Also $\ _{w}\mu_{d} = \frac{\ _{a}\mu_{d}}{\ _{a}\mu_{w}}$
Given, $\ _{a}\mu_{d} = 2.4,\ _{a}\mu_{w} = 1.33$
$\therefore\ _{w}\mu_{d} = \frac{2.4}{1.33} = 1.6$