(b) Time of exposure $\propto (f.\ number)^{2} \Rightarrow \frac{t_{2}}{t_{1}} = \left( \frac{5.6}{2.8} \right)^{2} = 4$ $t_{2} = 4t_{1} = 4 \times \frac{1}{200} = \frac{1}{50}sec = 0.02\ sec$
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Ph.D. in Physics with 19+ years of teaching experience.