(b) Here, $P_{1} + P_{2} = 2D\ and\ P_{1} = 5D$
So $P_{2} = \ - 3\ D$
For an achromatic combination
$\omega_{1}P_{1} + \omega_{2}P_{2} = 0$
$or\ \ \ \frac{\omega_{1}}{\omega_{2}} = \left( - \frac{P_{2}}{P_{1}} \right) = - \frac{( - 3)}{2} = \frac{3}{5}$