Q. With respect to air critical angle in a medium for light of red colour $(\lambda_{1})$ is $\theta$. Other facts remaining same, critical angle for light of yellow colour $\lbrack\lambda_{2}\rbrack$ will be

A) $\theta$
B) More than $\theta$
C) Less than $\theta$
D) $\frac{\theta\lambda_{1}}{\lambda_{2}}$
Explanation

(c) Critical angle $= \sin^{- 1}\left( \frac{1}{\mu} \right)$
$\therefore\theta = \sin^{- 1}\left( \frac{1}{\mu_{\lambda_{1}}} \right)$ and $\theta^{'} = \sin^{- 1}\left( \frac{1}{{\mu_{\lambda}}_{2}} \right)$
Since $\mu_{\lambda_{2}} > {\mu_{\lambda}}_{1}$, hence $\theta^{'} < \theta$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.