(b) $\frac{1}{u} + \frac{1}{v} = \frac{1}{f}\ $or$\ \frac{1}{v} = - \frac{1}{u} + \frac{1}{f}$ Now, compare with $y = mx + c$ Therefore graph is a straight line having negative slope
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.